The Tx does not see an SWR it sees an impedance, it is the transmission line that has the standing waves and that must be based on the impedance of the line NOT the load that the Tx 'likes to see'. Th

You are still not getting it are you. The point that I am trying to get you to see is that a 2:1, or any other vswr for that matter, can have an effect above and beyond the numbers that you are quotin

Indeed, but you are ignoring 2 important factors; 1) the tx does not match the cable impedance, Your examples assume a matched source with all of the reflected power absorbed, and 2) how the PA reacts

Reflection loss is the ratio of incident power to the reflected power at a discontinuity or impedance mismatch. So for a 2:1 vswr it is 0.889 or 0.512dB, meaning that 0.111 of the incident power (11%)

Multiple reflections is certainly not a myth and the reflected power is real (and may be sampled or removed with things such as circulators and directional couplers). The standing wave is only there b

Warren you are totally missing my points: Firstly, you stated that the reflection loss of a 2:1 vswr was variable. I am try to point out that the RL of a 2:1 mismatch is fixed and clearly defined, add

The point that you are missing is that the reflection loss stated is that at the Tx end of the coax., ie after the vswr caused by the 2:1 mismatch has been mitigated to some extent by the loss of the

Have a look at: <https://www.allaboutcircuits.com/tools/vswr-return-loss-calculator/> It would appear that Transmission Line Details is giving you a misleading picture. It seems to be telling you what

The loss attributable to a 2:1 VSWR can be stated as a constant,; the reflection loss from a 2:1mismatch is 0.512dB. Wwhat is variable is the loss before the incident power hits the mismatch, and what

Both or may be neither! Look up wave particle duality. 73 Jeff G8HUL

Indeed, but there will be a measurable standing wave on the line, due to the reflected wave from the mismatch at the antenna. How that reflected wave interacts at the source is a completely different

That is not correct. If the wave on a transmission line encounters an impedance other that that of the transmission line there will be a reflected wave at that point, regardless of the impedance of th

..and that is why ham radio is going to the dogs. Not many seem interested in the technical side of the hobby any more. they just want multi band CB, buy a black box and exchange numbers and collect s

However, there is always loss and the radiation resistance of the antenna, there will be a resistive part at the point where L and C cancel. Without that the circuit would have infinitive Q. So the de

A 5/8 does not require any matching other than a series coil, in fact there are 5/8 2m mobile whips that consist of just an open coil at the base of the whip. If there is a more complex matching circu

Indeed, any antenna of any length will radiate ALL of the power applied to it, less any resistive losses due to the material. Conservation of energy applies; the trick of course is how you get the pow

Just to point out that what was proposed by Smith was not scaled to the system impedance. The Smith chart was centred on 1 ohm and all point had to be normalized to 1 ohm, and then un-normalized to wo

Also Kelvin (K) only replaced Degrees Absolute in 1968! Regards Jeff

I think that is overstating the case a bit Dave. If a low SWR exists then the return loss is by definition low, so that means that the power is going somewhere other than back to the Tx. It may be tha

That is not correct, 4nec2 has 2 excellent built in editors for producing cards, , as well as a straightforward text editor, and a graphical 2D/3D editor which is much better than the EZNEC offering.